[LUA] Export waypoints

Doug · August 16, 2006

Hi !

I'm working to build a complete navigation system.

I have a problem with the x,y,z position of waypoints.

How have the position of my aircraft with the same x,y,z system ?

I only have a function wich give me LatLongAlt but no x,y,z.

LoGetRoute()  -- (args - 0,results = table)
get_route_result =
{
   goto_point, -- next waypoint
   route       -- all waypoints of route (or approach route if arrival or landing)
}
waypoint_table =
{
   this_point_num,        -- number of point ( >= 0)
   world_point = {x,y,z}, -- world position in meters
   speed_req,             -- speed at point m/s 
   estimated_time,        -- sec
   next_point_num,           -- if -1 that's the end of route
}

Regards

Alex Okean · August 16, 2006

Hi !

I'm working to build a complete navigation system.
I have a problem with the x,y,z position of waypoints.
How have the position of my aircraft with the same x,y,z system ?
I only have a function wich give me LatLongAlt but no x,y,z.
LoGetRoute()  -- (args - 0,results = table)
get_route_result =
{
   goto_point, -- next waypoint
   route       -- all waypoints of route (or approach route if arrival or landing)
}
waypoint_table =
{
   this_point_num,        -- number of point ( >= 0)
   world_point = {x,y,z}, -- world position in meters
   speed_req,             -- speed at point m/s 
   estimated_time,        -- sec
   next_point_num,           -- if -1 that's the end of route
}
Regards

sorry it's our mistake , ( i forgot to add this routines to 1.12 export , they are will be available in BS)

but try to use this code


float MapCoords::zeroX = 5000000.f; 
float MapCoords::zeroZ = 6600000.f;
// data for recalculation

float MapCoords::centerX = 11465000.f - zeroX; // circle center
float MapCoords::centerZ =  6500000.f - zeroZ;

float MapCoords::pnSxW_X = 4468608.57f - zeroX; // point 40dgN : 24dgE
float MapCoords::pnSxW_Z = 5730893.72f - zeroZ;

float MapCoords::pnNxW_X = 5357858.31f - zeroX; // point 48dgN : 24dgE
float MapCoords::pnNxW_Z = 5828649.53f - zeroZ;

float MapCoords::pnSxE_X = 4468608.57f - zeroX; // point 40dgN : 42dgE
float MapCoords::pnSxE_Z = 7269106.20f - zeroZ;

float MapCoords::pnNxE_X = 5357858.31f - zeroX; // point 48dgN : 42dgE
float MapCoords::pnNxE_Z = 7171350.00f - zeroZ;

// 
double MapCoords::lenNorth = sqrt((pnNxW_X-centerX)*(pnNxW_X-centerX) + (pnNxW_Z-centerZ)*(pnNxW_Z-centerZ));
double MapCoords::lenSouth = sqrt((pnSxW_X-centerX)*(pnSxW_X-centerX) + (pnSxW_Z-centerZ)*(pnSxW_Z-centerZ));
double MapCoords::lenN_S = lenSouth - lenNorth;

double MapCoords::RealAngleMaxLongitude = atan (((double)pnSxW_Z - centerZ)/(pnSxW_X - centerX)) * 180.f / PI;
// borders
float MapCoords::EndWest = 24.f;
float MapCoords::EndEast = 42.f;
float MapCoords::EndNorth = 48.f;
float MapCoords::EndSouth = 40.f;
float MapCoords::MiddleLongitude = (EndWest + EndEast) / 2;
float MapCoords::ToLengthN_S = (float)((EndNorth - EndSouth) / lenN_S);
double MapCoords::ToAngleW_E = (MiddleLongitude - EndWest) / RealAngleMaxLongitude;

double MapCoords::Longitude(float x, float z)	// degrees , (x (meters) - to North, z (meters) - to East)
{
double ang = - atan (((double)(z - centerZ)) / (x - centerX)) * ToDegree;
return ang * ToAngleW_E + MiddleLongitude;
}

double MapCoords::Latitude(float x, float z)	// degrees (x (meters) - to North, z (meters) - to East)
{
double len = lenSouth - sqrt((x-centerX)*(x-centerX) + (z-centerZ)*(z-centerZ));
return len * ToLengthN_S + EndSouth;
}

void MapCoords::GetCoords(double inLatitudeDegrees, double inLongitudeDegrees, float &outX, float &outZ)
{
// Lo coordinates system
double realAng = (inLongitudeDegrees - MiddleLongitude) / ToAngleW_E / ToDegree;	
double realLen = lenSouth - (inLatitudeDegrees - EndSouth) / ToLengthN_S;
outX = centerX - realLen * cos (realAng);
outZ = centerZ + realLen * sin (realAng);
}

Doug · August 16, 2006

Yesssss :)

Thank you very much Alex !!!

Regards.

Doug

Doug · August 16, 2006

Here you can found LUA fonctions of Alex's work:

--data for recalculation
zeroX = 5000000
zeroZ = 6600000

centerX = 11465000 - zeroX --circle center
centerZ =  6500000 - zeroZ

pnSxW_X = 4468608 - zeroX -- point 40dgN : 24dgE
pnSxW_Z = 5730893 - zeroZ

pnNxW_X = 5357858 - zeroX -- point 48dgN : 24dgE
pnNxW_Z = 5828649 - zeroZ

pnSxE_X = 4468608 - zeroX -- point 40dgN : 42dgE
pnSxE_Z = 7269106 - zeroZ

pnNxE_X = 5357858 - zeroX -- point 48dgN : 42dgE
pnNxE_Z = 7171350 - zeroZ

lenNorth = math.sqrt((pnNxW_X-centerX)*(pnNxW_X-centerX) + (pnNxW_Z-centerZ)*(pnNxW_Z-centerZ))
lenSouth = math.sqrt((pnSxW_X-centerX)*(pnSxW_X-centerX) + (pnSxW_Z-centerZ)*(pnSxW_Z-centerZ))
lenN_S = lenSouth - lenNorth

RealAngleMaxLongitude = math.atan ((pnSxW_Z - centerZ)/(pnSxW_X - centerX)) * 180/pi
-- borders
EndWest = 24
EndEast = 42
EndNorth = 48
EndSouth = 40
MiddleLongitude = (EndWest + EndEast) / 2
ToLengthN_S = ((EndNorth - EndSouth) / lenN_S)
ToAngleW_E = (MiddleLongitude - EndWest) / RealAngleMaxLongitude

ToDegree = 360/(2*pi)


function getLongitude(x, z)    -- degrees , (x (meters) - to North, z (meters) - to East)

   ang = - math.atan (((z - centerZ)) / (x - centerX)) * ToDegree
   return ang * ToAngleW_E + MiddleLongitude

end

function getLatitude(x, z)    --degrees (x (meters) - to North, z (meters) - to East)

   len = lenSouth - math.sqrt((x-centerX)*(x-centerX) + (z-centerZ)*(z-centerZ))
   return len * ToLengthN_S + EndSouth

end

function getXYCoords(inLatitudeDegrees, inLongitudeDegrees) -- args: 2 numbers // Return two value in order: X, Y

   -- Lo coordinates system
   realAng = (inLongitudeDegrees - MiddleLongitude) / ToAngleW_E / ToDegree
   realLen = lenSouth - (inLatitudeDegrees - EndSouth) / ToLengthN_S
   outX = centerX - realLen * cos (realAng)
   outZ = centerZ + realLen * sin (realAng)
   return outX, outY
end

To get latitude and longitude with X,Z coord, you have to do this:

myLat = getLatitude(myXCoord, myZCoord)

myLong = getLongitude(myXCoord, myZCoord)

To get X,Z coord with Lat/Long you have to do this (not usefull):

myXCoord, myZCoord = getXYCoords(myLat, myLong)

myLat and myLong are two float like 48.2034

To convert a latitude (°, min, sec):

floatDeg = integerDeg + (60*min + sec)/3600

Ex of Krymsk:

44° 57' 45" N --> 44 + (60*57 + 45)/3600 = 44.9625

Regards

Doug

dodger42 · August 16, 2006

Wow nice response. Alex I dont suppose you can say whether there will be other changes to LUA in BS? Fingers crossed! :)

Fufunka · August 17, 2006

Alex & Doug> can we hope that MFDs/FLIR/ABRIS views will be possible to export someday too? Like the MSFS, Falcon, FlighGear sims can do..

Doug · August 17, 2006

Actually we can't export all that we need to build a complete MFD. But we can do it without data like radar position etc.

I hope it will be possible in BS.

DarkSoul · August 17, 2006

Alex & Doug> can we hope that MFDs/FLIR/ABRIS views will be possible to export someday too? Like the MSFS, Falcon, FlighGear sims can do..

if BS supports MFD/Flir export.. then i will buy somekind 8" Lcd :joystick:

Fufunka · August 17, 2006

DarkSoul> Simmeters have already working version of Lockon glasspanel gauges and HUD view export so if they will support MFD/ABRIS/Flir you only add "few dozen" switches, displays and warning lights connected for instance via opencockpits IO cards.. Opencockpits architecture is already supported in Lockon FC, MSFS, IL2, Falcon, and EECH is in alpha now..

http://avia.transas.com/eng/abris.htm

Doug · October 30, 2006

Alex, I would to use the MAP of lockon to build a GPS.

This map is a Lambert map ?

What is the X and Z positions? Is it the projection of Lat/long position on the Lambert map of LockOn ?

I think it work like that:

Regards.

bnepethomas · October 30, 2006

Wow nice response. Alex I dont suppose you can say whether there will be other changes to LUA in BS? Fingers crossed! :)

Couple of things I am seriously hanging out for is gear, flap and brake status for the pit.

EvilBivol-1 · November 2, 2006

Doug, check your PMs, please.

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[LUA] Export waypoints

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