Turn rate charts

Do A-10A charts apply? If not, what is the source for DCS aircraft? Thanks.

I want to calculate required G for 18 degrees / sec turn rate carrying 2 mk-82's, tgp, alq-131 full cannon, and 50% fuel, at 3700 ft

Thanks

Yes A model charts apply. Even the latest C model -1 has A model charts.

thanks paulrkii.

Can be calculate with: G = 1 / cos ( Bank)

No need for charts. Just calculate the radius at the required (true) airspeed and then the centripetal acceleration. Finally, good old Pythagoras to find nz (i e the G loading).

You didn't post an airspeed, which is a required parameter.

Level turn, I applied SI units.

Turn rate ω=(deg/s)/180*π rad/s (1)

True air speed (in m/s) V=ω*r m/s => r=V/ω m(2)

Horizontal (centripetal) acceleration a=V^2/r m/s^2

Insert (2)

a=V^2/r=V^2*ω/V=Vω m/s^2

Insert (1)

a=V*(deg/s)/180*π m/s^2

g_centripetal=V*(deg/s)/180*π/g=V*(deg/s)/180*π/9.82

G load nz=sqrt(g_centripetal^2+1^2)=sqrt(a^2+g) =

sqrt((V*(deg/s)/180*π/9.82)^2+1)

G load nz= square root((V*(deg/s)/180*3.14/9.82)^2+1)

For zero turn rate

nz=sqrt(0^2+1)=1

Assume 90 m/s, around 170 KTAS and 18 deg/s.

nz=sqrt((90*18/180*3.14/9.82)^2+1)=3 g

The bank angle can be calculated from the centripetal acceleration from ba=atan(a/g)=atan(g_centripetal/1)

(Now play a good game of hunt the error - it's getting to 2200 here :) )

(And that is essentially the doghouse plot guidelines expressed algebraically)

omg this turned into maths fiasco!!! ok, my speed at turning would be 285 KIAS

omg this turned into maths fiasco!!!

You asked a question which is answered by physics/flight dynamics. You were given the tools to find the answer to your question, and you call it a fiasco?

Do we have a language barrier issue here regarding the word 'fiasco'?

4.8 g if TAS

5.0g if IAS

Mass of the airplane apparently plays no decisive role

Relax effte I was joking.